ScalarMap = mplcm.ScalarMappable(norm=cNorm, cmap=cm)
#PYPLOT SUBPLOT JULIA CODE#
The following code produces the same exact result: import matplotlib.pyplot as pltĬNorm = colors.Normalize(vmin=0, vmax=NUM_COLORS-1) The advantage of this method is that you can use a non-linear Normalization to convert from line index to actual color. I haven’t really used PyPlot in Julia for a while. I believe size (10, 200) simply calls size (x::Number, d), and returns 1 (as 10 is a scalar). There is an alternative way that uses a ScalarMappable object to convert a range of values to colors. The size function is not affecting the plot output size, in: using PyPlot x 1,2 y x plot (x,y) size (10,200) savefig ('./test.png') Without any result either. This is done in this example: import matplotlib.pyplot as pltĪx.set_color_cycle() Specifically you want to cycle form 0 to 19/20, because 1 maps back to 0. So for your 20 lines, you want to cycle from 0 to 1 in steps of 1/20. There a color map takes a value from 0 to 1 and returns a color.
#PYPLOT SUBPLOT JULIA GENERATOR#
You want to get the correct list of colors though, and this is most easily done using a color map, as is explained in the answer to this question: Create a color generator from given colormap in matplotlib. This is done with the t_color_cycle method.
#PYPLOT SUBPLOT JULIA HOW TO#
The answer to How to pick a new color for each plotted line within a figure in matplotlib? explains how to define the default list of colors that is cycled through to pick the next color to plot. The answer to your question is related to two other SO questions. You might also take a look at plt.figlegend(). Have a look at the matplotlib legend guide. # Shrink current axis's height by 10% on the bottomĪx.set_position([box.x0, box.y0 + box.height * 0.1,Īx.legend(loc='upper center', bbox_to_anchor=(0.5, -0.05), # Put a legend to the right of the current axisĪx.legend(loc='center left', bbox_to_anchor=(1, 0.5))Īnd in a similar manner, shrink the plot vertically, and put a horizontal legend at the bottom: import matplotlib.pyplot as plt Line, = ax.plot(x, i * x, label='$y = %ix$'%i)Īx.legend(loc='upper center', bbox_to_anchor=(0.5, 1.05),Īlternatively, shrink the current plot's width, and put the legend entirely outside the axis of the figure (note: if you use tight_layout(), then leave out ax.set_position(): import matplotlib.pyplot as pltĪx.set_position()
Similarly, make the legend more horizontal and/or put it at the top of the figure (I'm also turning on rounded corners and a simple drop shadow): import matplotlib.pyplot as plt If we do the same thing, but use the bbox_to_anchor keyword argument we can shift the legend slightly outside the axes boundaries: import matplotlib.pyplot as plt So, let's start with a generic example: import matplotlib.pyplot as plt To add to what and already said, you can use the bbox_to_anchor keyword argument to place the legend partially outside the axes and/or decrease the font size.īefore you consider decreasing the font size (which can make things awfully hard to read), try playing around with placing the legend in different places: Since type constructors fall back to convert methods.There are a number of ways to do what you want. This may have arisen from a call to the constructor MethodError(.), LoadError: MethodError: Cannot `convert` an object of type String to an object of type MethodError I tried the latter to create a tuple but got an error: plot(tuple(, aspect_ratio=:equal, clims=(-1,1)) for i in 1:8].)) Heatmap(a, aspect_ratio=:equal, clims=(-1,1), title=string(3)))īut if I want to do all eight (or a variable number which is my goal), I can't make it work with a loop or a splat.
Heatmap(a, aspect_ratio=:equal, clims=(-1,1), title=string(2)), On Julia v0.5 rc3 and PyPlot v'2.2.1+', the above mentioned code just works as is on the REPL and also by running in non-interactive mode like, julia plot.jl. If I want to plot some of the 5x5 slices as heatmaps, I can do: plot(heatmap(a, aspect_ratio=:equal, clims=(-1,1), title=string(1)),
For example with an array a: a = randn(5,5,8) This plot function takes a varargs input and makes them into subplots, but I can't seem to feed my array in properly and am probably overlooking something simple. I want to make a set of subplots from a multidimensional array using Breloff's Julia Plots.
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